we are given
[tex] (x-2)^2-3=1 [/tex]
we can seperate them
First function is
[tex] y=(x-2)^2-3 [/tex]
second function is
[tex] y=1 [/tex]
now, we can draw graph
and find intersection points
so, we can see that
intersection points are
(0,1) and (4,1)
so, solutions are
[tex] x=0,x=4 [/tex]...........Answer
