[tex] \frac{3ab^{2} - d^{3}}{a}[/tex]
[tex] \frac{3(-\frac{1}{2})(4)^{2} - (-3)^{3}}{-\frac{1}{2}} [/tex]
[tex] \frac{3(-\frac{1}{2})(16) + 27}{-\frac{1}{2}} [/tex]
[tex] \frac{3(-8) + 27}{-\frac{1}{2}} [/tex]
The answer is B.
[tex] \frac{-24 + 27}{-\frac{1}{2}} [/tex]
[tex] \frac{3}{-\frac{1}{2}} [/tex]
[tex] -6 [/tex]
