Respuesta :

gmany

[tex]C^n_m=\left(\begin{array}{ccc}m\\n\end{array}\right)=\dfrac{m!}{n!(m-n)!}\\\\C^6_8=\left(\begin{array}{ccc}8\\6\end{array}\right)=\dfrac{8!}{6!(8-6)!}=\dfrac{6!\cdot7\cdot8}{6!\cdot2!}=\dfrac{7\cdot8}{1\cdot2}=\dfrac{56}{2}=28[/tex]

Jadepchavez

Answer:

28 because I have done this

Step-by-step explanation: