Answer: [tex]\bold{d)\quad \sqrt{6x^2-1}}[/tex]
Step-by-step explanation:
[tex]f(x)=\sqrt{2x-5}\qquad g(x)=3x^2+2\\\\\\f(g(x))=\sqrt{2(3x^2+2)-5}\\\\.\qquad \quad =\sqrt{6x^2+4-5}\\\\.\qquad \quad =\sqrt{6x^2-1}[/tex]
