Answer:
[tex]\large\boxed{y+3=\dfrac{3}{2}(x+4)}[/tex]
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
We have
[tex]m=\dfrac{3}{2},\ (-4,\ -3)[/tex]
Substitute:
[tex]y-(-3)=\dfrac{3}{2}(x-(-4))\\\\y+3=\dfrac{3}{2}(x+4)[/tex]
