Solution:
Given that,
[tex]y = x^2 - 4 ------- eqn\ 1\\\\y = -3 ---------- eqn\ 2[/tex]
We have to find the solution (x, y)
Substitute eqn 2 in eqn 1
[tex]-3 = x^2 - 4[/tex]
[tex]x^2 = -3 + 4\\\\x^2 = 1\\\\Take\ square\ root\ on\ both\ sides\\\\x = \pm 1[/tex]
Thus, we get,
x = 1
x = -1
Thus the solution is (1, -3) or (-1, -3)
