Answer:
5 and - 1
Step-by-step explanation:
2x^2-8x-10=0
a=2,b=-8,c=-10
x1=(-b+sqrt(b^2-4ac))/2a
x1 =(-(-8)+sqrt ((-8)^2-4*2*(-10))/2*2
x1=(8+sqrt (64+80))/4
x1 =(8+sqrt (144))/4
x1=(8+12)/4
x1=20/4
x1 =5
x2=(-b-sqrt(b ^2-4ac)) /2 *a
x2=(8-12)/4
x2=-4/4
x2=-1
