Answer:
f (g (pi/2)=0
Step-by-step explanation:
we have the following functions:
f (x)=sinx
g (x)=cosx
the first thing we must do in the case is composition of functions:
f (g (x)
By making the composition we have:
f (g (x)=sin.cos.(x)
we evaluate for x=pi/2:
f (g (pi/2)=sin.cos(.pi/2 )
=sin (0)
=0
