Answer: D) cube root of 16
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Explanation:
The rule we use is
[tex]x^{m/n} = \sqrt[n]{x^m}[/tex]
In this case, x = 4, m = 2 and n = 3.
So,
[tex]x^{m/n} = \sqrt[n]{x^m}\\\\\\4^{2/3} = \sqrt[3]{4^2}\\\\\\4^{2/3} = \sqrt[3]{16}\\\\\\[/tex]
Showing that the original expression turns into the cube root of 16.
