Respuesta :

Student 1 and student 3 are equivalent
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Answer:

A. Students 1 and 3

Step-by-step explanation:

Student 3's equation is -5r + 3s - 1

Student 1's equation is -(5r - 3s + 1)

We distribute the negative like this: -5r + 3s - 1, which is the same as student 1.

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