Answer:
l = (3x+5)
Step-by-step explanation:
Given that,
The area of a room, [tex]A=3x^2-x-10[/tex]
The width of the room, [tex]b=(x-2)[/tex]
We need to find the length of the room.
The area of the room is given by :
A = lb
[tex]l=\dfrac{A}{b}\\\\l=\dfrac{3x^2-x-10}{x-2}\\\\l=\dfrac{(x-2)(3x+5)}{x-2}\\\\l=(3x+5)[/tex]
So, the length of the room is equal to (3x+5).
