Answer:
Molarity of 40 ml of NaoH is 0.3125 mL
Explanation:
As we know
Molarity of acid * volume of acid = molarity of base * volume of base
Substituting the given values, we get
[tex]0.5 * 25 = X* 40 \\X = \frac{0.5*25}{40} \\X = 0.3125[/tex]
Molarity of 40 ml of NaoH is 0.3125 mL
