Answer:
Step-by-step explanation:
cos theta=4[tex]\sqrt{2}[/tex]/7
so here adjacent=4[tex]\sqrt{2}[/tex] ,hypotenuse=7 ,opposite=?
h^2=p^2+b^2
7^2=(4[tex]\sqrt{2}[/tex] )^2+b^2
49-32=b^2
[tex]\sqrt{17}[/tex] =b
sin theta=opposite/hypotenuse
=[tex]\sqrt{17[/tex]/7
