Step-by-step explanation:
Taking the derivative of both sides with respect to x, we get
[tex]\dfrac{d}{dx}(x^3 + y^3) = \dfrac{d}{dx}(3)[/tex]
[tex]\Rightarrow 3x^2 + 3y^2\dfrac{dy}{dx} = 0[/tex]
Solving for [tex]\frac{dy}{dx}[/tex], we get
[tex]\dfrac{dy}{dx} = -\dfrac{3x^2}{3y^2} = -\dfrac{x^2}{y^2}[/tex]
