Respuesta :

hello! your answer would be infinite solutions, or b! hope this helped! ;)
ayanokoji1710

Answer:

Step-by-step explanation

3(k+9)=8-(-3k-19)

=> 3k+27=8+3k+19

=>3k+27-8-3k-19=0

=>0=0

so with all value of k, 3(k+9)=8-(-3k-19) always