Answer:
Step-by-step explanation:
[tex]12^{2x-1}=(\sqrt[4]{12})^{x}\\\\ 12^{2x-1}= (12^{\frac{1}{4}})^{x}\\\\12^{2x-1}=12^{\frac{1}{4}*x}\\[/tex]
Bases are same. So, compare the exponents.
[tex]2x - 1 =\dfrac{1}{4}x[/tex]
Multiply the entire equation by 4
4*(2x - 1) = x
8x - 4 = x
8x = x + 4
8x -x = 4
7x = 4
x = 4/7
