Answer:
B. m∠A = [tex]tan^{-1}(\frac{20}{15} )[/tex]
Step-by-step explanation:
Angle A has opposite side = 20 and adjacent side = 15
Using sohcahtoa method,
[tex]\frac{opposite}{adjacent} = tan(A)[/tex]
[tex]\frac{20}{15} = tan(A)[/tex]
[tex]tan^{-1}(\frac{20}{15} ) = A[/tex] .....this is the answer.
m∠A = 53.1° .....angle m∠A
