katara2
katara2
01-03-2017
Mathematics
contestada
solve for y (y+2)^2=2y^2+14y+28
Respuesta :
sdmatera
sdmatera
01-03-2017
y=-6 and -4
y^2+4y+4=2y^2+14y+28
0=y^2+10y+24
0=(y+6)(y+4)
y=-6 y=-4
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