sharnii
sharnii
02-11-2017
Mathematics
contestada
I am having difficulty solving this problem
Respuesta :
jdoe0001
jdoe0001
02-11-2017
[tex]\bf \textit{area of this square}\\\\ A=s^2\qquad \boxed{s=42}\implies A=42^2\implies A=\stackrel{inches}{1764}\\\\ -------------------------------\\\\ \textit{area for this rectangle}\\\\ A=lw\quad \begin{cases} w=26\\ l=73\frac{2}{3}\\\\ \qquad \frac{73\cdot 3+2}{3}\\\\ \qquad \frac{221}{3} \end{cases}\implies A=\cfrac{221}{3}\cdot 26\implies A=\cfrac{5746}{3} \\\\\\ A=\stackrel{inches}{1915\frac{1}{3}}\\\\ -------------------------------\\\\[/tex]
[tex]\bf \textit{area for this circle}\\\\ A=\pi r^2\quad \begin{cases} diameter=36\\ r=radius=\frac{diameter}{2}\\ r=18 \end{cases}\implies A=\pi 18^2\implies A=324\pi \\\\\\ A\approx \stackrel{inches}{1017.876019763}[/tex]
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