Hi there!
Due to the following algebra rule:
[tex] \frac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b} [/tex]
We get the following outcome:
[tex] \frac{x {}^{ \frac{1}{3} } }{ {x}^{ \frac{1}{12} } } = x {}^{ \frac{1}{3} - \frac{1}{12} } = {x}^{ \frac{1}{4} } [/tex]
