Answer:
Factor by grouping Ab+4+a+4b
[tex](b+1)(a+4)[/tex]
Step-by-step explanation:
Factor by grouping:
[tex]ab+4+a+4b[/tex] (1)
We have some common terms, the term a and the number 4: [tex]ab+a+4+4b\\a(b+1)+4(b+1)[/tex]:
Now, we have other common term, (b+1)
[tex]a(b+1)+4(b+1)\\(b+1)(a+4)[/tex]
