[tex]\bf \qquad \textit{Amount for Exponential Growth}
\\\\
A=P(1 + r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &450\\
r=rate\to 6.5\%\to \frac{6.5}{100}\to &0.065\\
t=\textit{elapsed time}\\
\end{cases}
\\\\\\
A=450(1+0.065)^t\implies A=450(\stackrel{growth~factor}{1.065})^t[/tex]
